Posted by **Kayla** on Friday, November 21, 2008 at 3:54am.

a uniform bridge span weighs 50000N and is 40m long. An automobile weighing 15000N is parked with its center of gravity located 12m from the right pier. What upward support does the left pier provide?

- Physics center of gravity -
**drwls**, Friday, November 21, 2008 at 6:35am
To get the upward force F on the left pier, set the total moment about the right pier equal to zero. The 50,000 N weight of the bridge acts through its CG, which is at the middle of the bridge. The weight of the car acts 28 m from the left pier,in the same direction. The force on the left pier produces a moment in the opposite direction.

50,000*20 + 15,000*28 - F*40 = 0

Solve for F

- Physics center of gravity -
**philip**, Sunday, September 23, 2012 at 11:46am
29500

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