Posted by Kayla on Friday, November 21, 2008 at 3:54am.
To get the upward force F on the left pier, set the total moment about the right pier equal to zero. The 50,000 N weight of the bridge acts through its CG, which is at the middle of the bridge. The weight of the car acts 28 m from the left pier,in the same direction. The force on the left pier produces a moment in the opposite direction.
50,000*20 + 15,000*28 - F*40 = 0
Solve for F
29500
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