Posted by **Allie** on Thursday, November 20, 2008 at 2:04am.

how would you solve 3/(x+2) - 6/3x = 6/(3x+6) algebraically and graphically?

- pre-calc -
**drwls**, Thursday, November 20, 2008 at 7:32am
First rewrite the left side with a common denominator as:

[9x - 6(x+2)]/(3x^2+6x)

= (3x -12)/(3x^2+6x)

Then multiply the numerator and denominator of the right side by x. That does not change its value but gives you the same denominator on both sides. In that situation the numerators are equal, so

3x - 12 = 6x

3x = -12

x = -4

Check: -3/2 +6/12 =?= 6/-6 = -1 ok

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