Posted by raymond on Thursday, November 20, 2008 at 1:50am.
m1 = F/3.3
m2 = F/1.5
so
(m1+m2) = F(1/3.3 + 1/1.5) = .970 F
a = F/(.970 F) = 1.03 m/s^2
The mass m2 is larger than m1 by a factor
3.30/1.50 = 2.2
The combined mass m1 + m2 is therefore
m1 + 2.2m1 = 3.2 m1
When the same force F acts, acceleration will be ne 3.2 tikmes less than when it acted on m1, or
a = 3.30 m/s^2/3.2 = 1.03 m/s^2
Related Questions
physics - A force F applied to an object of mass m1 produces an acceleration of ...
Physics (Mathmate) - When a force is applied to an object with mass equal to the...
physics - When a force is applied to an object with mass equal to the standard ...
Physics - When certain a force is applied to a 2kg standard mass, its ...
Applied Physics - A 10 kilogram object subjected to a 20 Newton force moves ...
physics - A constant force is applied to an object, causing the object to ...
physics - A six kilogram object undergoes an acceleration of 2.0 meters per ...
Physics - Newton's second law states that if an object has zero acceleration...
physics - A 6.0 kg object undergoes an acceleration of 2.0 m/s2.a. What is the ...
Physics - An object with a mass of 2.489x10^1 kg is subjected to a force of 4....
For Further Reading
