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December 20, 2014

December 20, 2014

Posted by **mary** on Wednesday, November 19, 2008 at 10:51am.

Asinx-Bcosx+6Acosx+6Bsinx=3-cosx

when you group all the sinx and cosx

you get

(A+6B)sinx+(6A-B)cosx=3-cosx

you get

(A+6B)=0 and (6A-B)=-1<<<<<<<<<

i am having a hard time understanding the second part where i have the <<<< next to it...i mean shouldnt it be =-3 i really dont get that...i got this answer from the back of the book but i am trying to understand it...please help if possible...

- PLZZZ -
**mary**, Wednesday, November 19, 2008 at 11:59amplz someone help me...if anyone knowssssssss

- grouping -
**bobpursley**, Wednesday, November 19, 2008 at 1:20pmThe point of what you are doing is finding a particular solution. Ignore the -3, get the like coefficents as in the text, solve for A,B. Then you go back and try the solution you found to see if it works in the differential equation. If it does, you are ok with a particular solution. If it does not, often that checking will suggest a modification to your solution. This method is not exact, it sometimes takes iterations.

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