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July 24, 2014

July 24, 2014

Posted by **Natash** on Saturday, November 15, 2008 at 4:47pm.

tan^2x-sec^2x

- trig -
**drwls**, Saturday, November 15, 2008 at 4:53pmYou have not provided an equation.

Equations have an "=" sign.

You must have left something out.

Perhaps they just want you to write the term tan^2x-sec^2x in terms of sines and cosines. If so, they should have said so.

- trig -
**Reiny**, Saturday, November 15, 2008 at 5:00pmfrom the main Pythagorean Identity we know

tan^2 x + 1 = sec^2 x

so tan^2x-sec^2x = tan^2 x - (tan^2 x + 1)

= -1

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