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March 29, 2015

March 29, 2015

Posted by **sarah** on Saturday, November 15, 2008 at 1:01pm.

theta=(0.7t) rad

and

z=(-0.5t) m

where t is in seconds. How do you find the components of forces Fr, Ftheta and Fz which the slide exerts on teh boy at the instant when t=2s. Neglect the size of the boy.

- engineering -
**Damon**, Saturday, November 15, 2008 at 7:57pmI need to know r

w = d theta/dt = .7

Fr = 40 r w^2 = 40 r (.49) inward (negative r direction)

the tan of angle of the slide down from horizontal = .5/(wr) = .5/(.7r) = .714/r

Fz = weight of boy up = 40*9.8 = 392 N

Ftheta = weight tan angle = 392 (.714/r)

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