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September 21, 2014

September 21, 2014

Posted by **Austin** on Thursday, November 13, 2008 at 10:20pm.

Luis bought eight bags of candy at the store for a total price of $21.54. He bought some bags of candy that cost $2.22 each and the rest cost $3.48 each. How many bags of the $3.48 candy did Luis buy?

Responses

Math - qwerty, Thursday, November 13, 2008 at 9:23pm

A=2.22

B=3.48

A + B = 8

2.22A x 3.48B = 21.54

solve for B

Math - Austin, Thursday, November 13, 2008 at 10:08pm

I got this far, but how do I solve for B?

Math - bobpursley, Thursday, November 13, 2008 at 9:24pm

C means cheap candy bag, E means expensive candy bag.

C*2.22+E*3.48=21.54

C+E=8

- math -
**bobpursley**, Thursday, November 13, 2008 at 10:21pmA=8-B

Put that into the other equation for A, and then solve for B.

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