1) Nobelium has a half-life of 1 hour. If you start with 1 kg, how much will you have by this time tomorrow?

2) You have 90 g of Lawrencium. You step away to watch one episode of "everybody loves raymond." when you return to your scientific studies, you only have 0.088g of lawrencium. what is its half-life?

1) 1 kg * (1/2)^24

2. .088/90 = (1/2)^(t/T)

t is the length of an episode of that programm (30 minutes?). T is the half life of the isotope. Solve for T

is the second one 10 minutes?

i don't understand the first ine still. I got 6 but that does not make any sense at all

1) to answer question 1, we need to understand the concept of half-life. The half-life of a substance is the time it takes for the amount of that substance to decrease by half. In this case, the half-life of Nobelium is 1 hour.

To find out how much Nobelium you will have by this time tomorrow, we need to calculate how many half-lives have passed in 24 hours. Since the half-life is 1 hour, there are 24 half-lives in 24 hours.

Every time a half-life passes, the amount of Nobelium is halved. So, if we start with 1 kg, after 1 half-life we have 0.5 kg, after 2 half-lives we have 0.25 kg, after 3 half-lives we have 0.125 kg, and so on.

After 24 half-lives (24 hours), we would have (1/2)^24 kg of Nobelium left. This equals approximately 5.96 x 10^-8 kg or 0.0596 mg.

Therefore, by this time tomorrow, starting with 1 kg of Nobelium, we would have approximately 0.0596 mg left.

2) To answer question 2, we are given that you started with 90 g of Lawrencium and after watching one episode of "Everybody Loves Raymond" you returned to find only 0.088 g left.

The remaining amount of Lawrencium is 0.088 g out of the initial amount of 90 g.

To find the half-life, we need to determine how many times the original amount was halved to reach the remaining amount.

We can use the formula: remaining amount = initial amount * (1/2)^(number of half-lives).

Plugging in the values we have, 0.088 g = 90 g * (1/2)^(number of half-lives).

To solve for the number of half-lives, we need to take the logarithm base 1/2 of both sides of the equation.

log base 1/2 (0.088 g / 90 g) = number of half-lives.

Using a calculator, we find that the logarithm base 1/2 of (0.088 g / 90 g) is approximately 6.315.

Therefore, the number of half-lives is approximately 6.315.

Since the half-life is the time it takes for a substance to halve, we can conclude that the half-life of Lawrencium is approximately 6.315 times the duration of one episode of "Everybody Loves Raymond."

Note: This assumes that the decay of Lawrencium follows an exponential decay pattern, typically seen in radioactive decay.