Posted by **Craig** on Wednesday, November 12, 2008 at 11:27pm.

original curve: 2y^3+6(x^2)y-12x^2+6y=1

dy/dx=(4x-2xy)/(x^2+y^2+1)

a) write an equation of each horizontal tangent line to the curve

b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P.

-when plugging y as 2 in original, it doesn't work. what did i do wrong?

## Answer This Question

## Related Questions

- Help Calc.! - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1...
- please help; calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+...
- calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...
- Calculus - Please help this is due tomorrow and I dont know how to Ive missed a ...
- Calc AB - Suppose that f(x) is an invertible function (that is, has an inverse ...
- calculus - Find all points on the curve x^2y^2+xy=2 where the slope of tangent ...
- Calculus - the curve: (x)(y^2)-(x^3)(y)=6 (dy/dx)=(3(x^2)y-(y^2))/(2xy-(x^3)) a...
- Calculus [finding slope of tangent line] - Find the slope of the tangent line to...
- AP Calc. AB - At how many points on the curve y=4x^5-3x^4+15x^2+6 will the line ...
- Calculus - Consider the curve given by y^2 = 2+xy (a) show that dy/dx= y/(2y-x...

More Related Questions