Posted by **Craig** on Wednesday, November 12, 2008 at 11:27pm.

original curve: 2y^3+6(x^2)y-12x^2+6y=1

dy/dx=(4x-2xy)/(x^2+y^2+1)

a) write an equation of each horizontal tangent line to the curve

b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P.

-when plugging y as 2 in original, it doesn't work. what did i do wrong?

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