Posted by **James** on Wednesday, November 12, 2008 at 11:05pm.

2Sin(Θ+47°)=1 ΘЄ[0°, 360°)

What I did:

Sin(Θ+47°)=1/2

Sin 1/2 = Θ+47°

30°+360 = Θ+47°

343° = Θ

Ok, so how do i find the other solutions? In this problem its 103°. I think we were suppose to do something with the graphing calculator and something about calculating the zero. I know how to do that, but i dont know how to make it equal 0 so i could put it in Y1? Any other way, what did i do wrong? Is there a prgm that is avilable for the Ti-83+ that can do these problems?

btw:

Θ = theta

Thanks in advance.

- Trig - Identies/equation, please help! -
**Sarah**, Wednesday, November 12, 2008 at 11:18pm
whtis the value of 343... figure tht out .. and thn u can say tht other solutions with be 2 pie ( n)

n wht ever value u figure out in radioans..

- Trig - Identies/equation, please help! -
**drwls**, Wednesday, November 12, 2008 at 11:18pm
That looks like an equation, not an identity. If it were an identity, it would be true for all theta.

I am confused about what your symbol on the right side,

1 ΘЄ[0°, 360°)

is supposed to mean

Are you solving 2 Sin(Θ+47°)= 1 ?

If so, Sin(Θ+47°)=0.5

Θ+47° = 30, 150 or 390 degrees

Θ = 103 or 333 degrees if you are limited to theta between 0 and 360 degrees

- Trig - Identies/equation, please help! -
**James**, Wednesday, November 12, 2008 at 11:41pm
the ΘЄ[0°, 360°) was suppose to mean its 0° < or = Θ < 360°

- Trig - Identies/equation, please help! -
**James**, Thursday, November 13, 2008 at 12:10am
I get this now!!, Thanks!!!, i guess i should study now.

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