Posted by Sam on Wednesday, November 12, 2008 at 10:52pm.
pH = pKa + log(B/A)
mols K2CO3 = M x L.
mols HCl = M x L.
Calculate mols K2CO3 initially.
Calculate mols HCl initially.
I think you will find that one H ion has been added to the CO3^=, and you are half way between CO3^= and H2CO3 meaning that CO3^= and H2CO3 are the same.
Therefore, log B/A = log 1 = 0 and pH = pKa1.
Post any work if you have questions.
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