February 22, 2017

Homework Help: chemistry

Posted by Sarah on Wednesday, November 12, 2008 at 9:12pm.

A piece of nickel foil, 0.550 mm thick, 1.25 cm width and 1.00 cm long, is allowed to react with fluorine, F2 to give a nickel fluoride. Density of nickel is 8.908 g/cm3. How many moles of nickel foil were used? If you isolated 1.261 g of nickel fluoride, what is its formula?

This is what I have come up with so far...

V = 0.055 cm x 1.25 x 1.00= 0.0688 cm^3

Mass = 0.0688 x 8.908 g/cm^3 = 0.612 g
moles Ni = 0.612 / 58.69 g/mol= 0.0104

Is that right? At all?


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