# Help Calc.!

posted by
**Rainie**
.

original curve: 2y^3+6(x^2)y-12x^2+6y=1

dy/dx=(4x-2xy)/(x^2+y^2+1)

a) write an equation of each horizontal tangent line to the curve

b) the line through the origin with the slope .1 is tangent to the curve at P. Find x and y of point P.