Posted by Morty on .
A 2.0Kg otter starts from rest at the top of a muddy incline 85 cm long and slides down to the bottom in .50s. What net force acts on the otter along the incline?
The force (F) equals the mass (M= 2.0 kg) times the acceleration.
If it travels 0.85 m in t = 0.50 s, the acceleration a is given by solving
0.85 = (1/2) a t^2 = = (a/2)*0.25
a = 6.8 m/s^2
Solve for F
formula=average acceleration=average velocity/total time