Posted by Morty on .
A 2.0Kg otter starts from rest at the top of a muddy incline 85 cm long and slides down to the bottom in .50s. What net force acts on the otter along the incline?

Physics 
drwls,
The force (F) equals the mass (M= 2.0 kg) times the acceleration.
If it travels 0.85 m in t = 0.50 s, the acceleration a is given by solving
0.85 = (1/2) a t^2 = = (a/2)*0.25
a = 6.8 m/s^2
Solve for F 
Physics 
tyreek,
13.6 n

Physics 
Hala,
givens:M=2.0kg,vi=0m/s,displacement=85cm(0.85m),t=0.50s.
formula=average acceleration=average velocity/total time
>>average velocity=displacement/time
>>average velocity=0.85/0.5=1.7m/s
>>average acceleration=1.7/0.5=3.4m/s^2
force=mass*acceleration
force=2.0*3.4=6.8N