Posted by kim on Tuesday, November 11, 2008 at 10:06pm.
You solve #1 and #3 by applying Newton's Second Law, F = m a.
For the second problem, you first need to solve for the required deceleration rate. a = F/m = 5 m/s^2
The time it takes to stop is
t = Vo/a = (30 m/s)/5 m/s^2 = 6 s
The distance travelled while stopping is that stopping time multiplied by the average velocity (Vo/2),
15 m/s * 6 s = 90 m
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