Posted by GiGi on Tuesday, November 11, 2008 at 7:46pm.
The spring is already stretched by the weight before is is pulled. That amount of "equilibrium" stretch is
Xe = M g/k = 0.674 m. Then the spring is pulled downward another 0.200 m for a total stretch of X = 0.874 m at the point of release. The kinetic energy is zero at that point, and the spring potential energy is (1/2)kX^2 = 18.33 J . Relative to the the point of release, the position is then h = 0. Call the gravitational potential energy zero at that point also.
The total energy of the system is the spring energy of 18.33 J
At h = 0.2, X = 0.674 m
At h = 0.4, X = 0.474 m
gravitational PE (gPE) = M g h
spring potential energy = (1/2) k X^2
kinetic energy = 18.33 J - KE - gPE
You complete the table
Related Questions
PHYSICS - A spring is hung from a ceiling, and an object attached to its lower ...
PHYSICS - A 0.49 kg object is attached to a spring with a spring constant 167 N/...
physics help! - Objects of equal mass are oscillating up and down in simple ...
physics - When a 2.60-kg object is hung vertically on a certain light spring ...
Physics help - A 1.0 kg object is suspended from a vertical spring whose spring...
physics - A 2.40 kg object is hanging from the end of a vertical spring. The ...
physics - the force exerted by a spring increases as the spring stretches. ...
phisics - An object is attached to the lower end of a 100-coil spring that is ...
physics help - A 1.0 kg object is suspended from a vertical spring whose spring ...
physics - A 10.4 kg object oscillates at the end of a vertical spring that has a...
For Further Reading
