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December 21, 2014

December 21, 2014

Posted by **Anonymous** on Tuesday, November 11, 2008 at 2:10pm.

- physics -
**Samantha**, Tuesday, November 11, 2008 at 2:29pmUse 1 of your kinematic equations twice. vfinal^2 = vinitial^2 + 2ad.

First you want to find the speed of the drag racer right when the parachute opens.

vfinal^2 = vinitial^2 + 2ad.

Substitute 0 for vinitial^2 and take the square root of 2(17)(402).

That becomes your initial velocity for when the parachute opens. Now you have to find the final velocity so sub what you get in for vfinal as vinitial^2 in

vfinal^2 = vinitial^2 + 2ad

vfinal^2 = vinitial^2 + 2(-6.10)(3.50x10^2).

- physics -
**bianca**, Sunday, September 7, 2014 at 7:27pm64.4

- physics -
**cody**, Tuesday, September 30, 2014 at 12:26am96.94

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