Posted by Rachelle on Monday, November 10, 2008 at 5:14pm.
Thanks for those who answered my previous question! I have just one more: x^2625=0, what is the GCF? How is it deterimined? It does not appear to me that there is one. How would it then be factored and have the zeroproduct powers applied?
Then, what about 120x^234x21=0 (The same procedures as the one above) Thank you so much again.

Algebra  Reiny, Monday, November 10, 2008 at 5:41pm
for x^2  625 =0
it factors to (x+25)(x25)= 0
take it from there
120x^234x21=0
I used the formula to find the solutions of x=7/12 and x=3/10
so the factored form must be
(12x7)(10x+3) = 0