Thanks for those who answered my previous question! I have just one more: x^2-625=0, what is the GCF? How is it deterimined? It does not appear to me that there is one. How would it then be factored and have the zero-product powers applied?
Then, what about 120x^2-34x-21=0 (The same procedures as the one above) Thank you so much again.
Algebra - Reiny, Monday, November 10, 2008 at 5:41pm
for x^2 - 625 =0
it factors to (x+25)(x-25)= 0
take it from there
I used the formula to find the solutions of x=7/12 and x=-3/10
so the factored form must be
(12x-7)(10x+3) = 0