Algebra
posted by Rachelle on .
Hi! I have a few questions about Factoring Quadratic Expressions.
My first one is 12x^2+x=6. How would you facor that?
My second is how would x^41 equal the answer 1(x^41)(x^2=1)(x^21)?
Finally, how would you factor something such as 3x(x+2)8(x+2), when there is no common factor other than one?
Thank you so much for your assistance! :)

12 x^2 + x  6 = 0
I solved the quadratic and got 2/3 and 3/4 so then tried
(3x+2)(4x3)=0 
x^41 is difference of two squares
(x^21)(x^2+1)
then
(x1)(x+1)(x^2+1) 
for 12x^2+x=6 write is as
12x^2+x6 = 0
then (3x2)(4x+3) = 0
x^41 factors to
(x^2 1)(x^2 + 1)
=(x1)(x+1)(x^2+1)
for 3x(x+2)8(x+2) you should see that ((x+2) is a common factor, so
3x(x+2)8(x+2)
= (x+2)(3x8)
= (x+2)(3x+8) 
3x(x+2)8(x+2)
sure there is a common factor  (x+2)
(x+2)(3x8)
(x+2)(1)(3x+8)