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October 25, 2014

October 25, 2014

Posted by **jessica** on Sunday, November 9, 2008 at 10:54pm.

prove-AB-EF (in 5 steps that show why it is corect; i.e two-column proof)

2)Given-<2=<3, <4=<5

prove-<1 is supplementay to <6

(in 3 steps, with the two column proof)

TWO-COLUMN PROOF LOOKS LIKE THIS....

STATEMENT: REASON:

1.AB=CD,CD=EF 1.Given

2.?? 2.??

3.?? 3.??

4.?? 4.??

5.AB=EF 5.??

- geometry -
**bobpursley**, Sunday, November 9, 2008 at 11:01pmTransitive Axiom If a = b and b = c then a = c

So it seems to me to be two steps, not five.

You second makes no sense, it does not indicate any relationship with <1 and any other angle.

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