Posted by Alice on Sunday, November 9, 2008 at 4:54pm.
Find the specific solution for the following differential equations:
a) (dy/dx)^2  x^4 = 0 given the initial value y(1) = 0
b) dy/dx = ysinx given the initial value y(pi) = 1

Math  bobpursley, Sunday, November 9, 2008 at 5:38pm
a) move the x^4 over, take the square root of each side.
dy/dx=x^2
y= 1/3 x^3 +C or y=1/3 x^3C
Specific solution? It looks to me that both will work.
dy/dx=x^2 dy/dx=x^2
y'^2=x^4 y'^2=x^4
and if you pursue it, there are two imaginary solutions also.
b)dy/y= dx*sinx
lny= cosx
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