What is the y-intercept of
f(x)=x^2+x-12?
the answers are
a.)(0,12)
b.)(-72,0)
c.)(0,-12)
d.)(0,-72)
I have the answer as (c.)(0,-12) is this right?
To find the y-intercept of a function, you need to determine the value of the function when x is equal to 0.
For the given function f(x) = x^2 + x - 12, we can find the y-intercept by substituting x = 0 into the equation:
f(0) = (0)^2 + (0) - 12
= 0 + 0 - 12
= -12
Therefore, the y-intercept of the function is (0, -12), which matches the answer you provided as (c.)(0, -12). So, your answer is correct.