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November 26, 2014

November 26, 2014

Posted by **Trig** on Sunday, November 9, 2008 at 2:16pm.

- Trigonometry -
**Reiny**, Sunday, November 9, 2008 at 3:03pmyour lack of the proper use of brackets make your equation much too ambiguous.

Furthermore, the brackets you do use, make no difference to the meaning.

If they are removed, there is no change in the order of operation, but ....

on the left side, who is divided by cos^2 x ?

is it -8/cos^2 x ? or

(8sinx-8)/cos^2 x or

(3cos^2x + 8sinx-8)/cos^2 x

each would give you a different result, the same is just as confusing on the right side.

- Trigonometry -
**Trig**, Sunday, November 9, 2008 at 3:31pm(3cos^2x + 8sinx-8)/cos^2x = (3sinx-5)/sinx+1

- Trigonometry -
**Reiny**, Sunday, November 9, 2008 at 4:09pmLS = (3(1-sin^x) + 8x - 8)/cos^2x

= (3-3sin^x+8x-8)/cos^2x

= -(3sin^2x - 8x + 5)/((1-sinx)(1+sinx))

= -(3sinx-5)(sinx-1)/((1-sinx)(1+sinx))

= (3sinx-5)(1 - sinx)/((1-sinx)(1+sinx))

= (3sinx-5)/(1+sinx)

= RS

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