methanoic acid react with potassium dichromate to form what?
A colorless solution and CO2 is formed as known
CO2 and H2O are the products of the oxidation of HCOOH.
The K2Cr2O7 will be reduced to Cr^+3, which is green, which doesn't agree with your statement about a colorless solution being formed. Water is colorless, of course, but the solution, which is the water + Cr(III) ion, is green.
When methanoic acid (also known as formic acid) reacts with potassium dichromate, several products can be formed depending on the reaction conditions. However, the most common and balanced reaction equation for this reaction is as follows:
2 HCOOH + K2Cr2O7 + 3 H2SO4 → Cr2(SO4)3 + K2SO4 + 8 H2O + 2 CO2
In this reaction, potassium dichromate (K2Cr2O7) acts as an oxidizing agent and methanoic acid (HCOOH) acts as a reducing agent. The reaction is carried out in the presence of sulfuric acid (H2SO4) as a catalyst.
The products of this reaction are:
1. Chromic sulfate (Cr2(SO4)3): This forms as a result of the reduction of potassium dichromate. It is a colored compound and generally appears as a reddish-brown solid.
2. Potassium sulfate (K2SO4): This is formed as a byproduct of the reaction.
3. Water (H2O): Water is produced as a result of the reaction between the acid and base present in the reactants.
4. Carbon dioxide (CO2): This gas is produced as a result of the oxidation of methanoic acid.
Overall, the reaction of methanoic acid with potassium dichromate results in the formation of a colored solution (due to the presence of chromic sulfate) and the release of carbon dioxide gas.