Saturday

March 28, 2015

March 28, 2015

Posted by **Anonymous** on Saturday, November 8, 2008 at 4:53pm.

limit of (e^h - 1)/h = 1 as h approaches 0

to show that the limit of [ln(x+h) -lnx]/h as h approaches 0 = 1/x, where x>0

- calculus -
**drwls**, Saturday, November 8, 2008 at 8:59pmln(x+h)-lnx = ln[1 + (h/x)=

-> h/x for x ->0

Divide that by h and you get 1/x. The limit as x->0 is infinity

I don't see how to use

limit of (e^h - 1)/h = 1 as h approaches 0 to solve this

e^h -1 -> h + h^2/2! + ... as h-> 0

**Answer this Question**

**Related Questions**

Differential Calculus - use the rule that says limit of (e^h - 1)/h = 1 as h ...

Differential Calculus - use the rule that says limit of (e^h - 1)/h = 1 as h ...

Calculus - Could someone please help me with these questions;I was having ...

Calculus - Find the limit as x approaches infinity of (lnx)^(1/x). This unit is ...

Calculus - 1. Evaluate the function at the given numbers (correct to six ...

calculus verify answer - Evaluate the limit: Limit as x approaches 6 from the ...

Calculus - 1. Use the Taylor series to calculate the limit. Problem: limit as x ...

Algebraic limits - The limit as x approaches infinity. (1)/(5^x) The limit as x ...

Calculus - Find limit as x approaches 1 5/(x-1)^2 A. 0 B. Negative infinity C. 5...

Calculus - Another one I'm not sure about is the limit as x approaches infinity ...