you slide down a pole at a mass of 80kg with an acceleration of 4m/s^2, How do you show that the friction force that acts on you is 480N?
Force = mass *acceleration
Force down = 80*9.8 = 784 N
force down - Ffriction = 80 (4)
solve for Ffriction
Weight - Friction force = M a
Friction force = Ma - Mg
= 5.8 m/s^2 * M
They apparently want you to use 10 m/s^2 for g, although the correct value is 9.8 m/s^2.
To show that the friction force acting on you while sliding down the pole is 480N, we need to use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.
Given:
Mass (m) = 80 kg
Acceleration (a) = 4 m/s^2
Step 1: Calculate the gravitational force acting on you.
The force due to gravity can be calculated using the formula:
Force (F) = mass (m) × acceleration due to gravity (g)
where the acceleration due to gravity (g) is approximately 9.8 m/s^2.
So, the gravitational force (F_gravity) acting on you is:
F_gravity = m × g
= 80 kg × 9.8 m/s^2
= 784 N
Step 2: Calculate the net force acting on you.
The net force is the vector sum of all forces acting on you. In this scenario, the only force acting on you is the friction force (F_friction). The net force (F_net) is given by:
F_net = F_friction
Step 3: Apply Newton's second law of motion.
According to Newton's second law, the net force (F_net) is equal to mass (m) multiplied by acceleration (a):
F_net = m × a
Step 4: Substitute the values into the equation.
Since F_net = F_friction,
F_friction = m × a = 80 kg × 4 m/s^2
= 320 N
Therefore, the friction force acting on you while sliding down the pole is 320N, not 480N. It's important to note that we have not considered any additional factors like air resistance or the angle of the pole, which may affect the actual value of the friction force.