# Differential Calculus

posted by
**Kristen** on
.

use the rule that says

limit of (e^h - 1)/h = 1 as h approaches 0

to show that the limit of [ln(x+h)-lnx]/h as h approaches 0 = 1/x, where x>0

posted by
**Kristen** on
.

use the rule that says

limit of (e^h - 1)/h = 1 as h approaches 0

to show that the limit of [ln(x+h)-lnx]/h as h approaches 0 = 1/x, where x>0