Posted by **Kristen** on Friday, November 7, 2008 at 4:20pm.

use the rule that says

limit of (e^h - 1)/h = 1 as h approaches 0

to show that the limit of [ln(x+h)-lnx]/h as h approaches 0 = 1/x, where x>0

Thursday

March 23, 2017
Posted by **Kristen** on Friday, November 7, 2008 at 4:20pm.

use the rule that says

limit of (e^h - 1)/h = 1 as h approaches 0

to show that the limit of [ln(x+h)-lnx]/h as h approaches 0 = 1/x, where x>0

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