February 24, 2017

Homework Help: genetics/biology

Posted by bebe on Friday, November 7, 2008 at 11:00am.

Bacteria Y has a mutation within it’s genome, at gene R, that provides resistance to neomycin. Bacteria Z is sensitive to neomycin, however, when Bacteria Y is placed in a mixture with Bacteria Z, Bacteria Z also gains neomycin resistance.

One cell of Bacterium Y undergoes another mutation at gene R which now provides resistance to neomycin and a closely related anti-biotic, streptomycin. Bacteria Y that has the mutated R gene that gives resistance to both neomycin and streptomycin will be called Y+. When Bacteria Y+ is placed in a mixture with Bacteria Z (that has never been exposed to Bacteria Y before), Bacteria Z does not gain neomycin or streptomycin resistance.

What can explain these results?

So basically:
Bacteria Y (res to neo) + Bacteria Z (sens to neo) = Bacteria Z (res to neo)

Bacteria Y+(res to neo & strep) + Bacteria Z(sens to neo)=Bacteria Z(sens to neo)

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