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March 4, 2015

March 4, 2015

Posted by **Sandhya** on Friday, November 7, 2008 at 4:46am.

the horizontal. The object’s initial speed is v = 2.0m/s. How far from

the start point does the object come to a stop if μK = 0.20?

- physics -
**drwls**, Friday, November 7, 2008 at 5:56amKietic friction will apply. There will be a backwards friction force opposing motion that is equal to

M g cos 5 * ěK = 1.95 m/s^2 * M

Motion will stop when the initial kinetic energy equals the gain in potential energy PLUS the work done against friction. Let X be the distance travelled. X sin 5 is the elevation gain.

(1/2) M V^2 = Mg cos5 ěK + MgX sin 5

Cancel out the M's and solve for X

V^2 = 2g [cos5 ěK + sin 5 X]

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