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October 1, 2014

October 1, 2014

Posted by **George** on Friday, November 7, 2008 at 12:43am.

(B) Find the equations of the normal lines to this circle at the same points. (The normal line is perpendicular to the tangent line at that point.)

(C) At what point do the two normal lines intersect?

For part A, I found that

16 + y 2= 25

y 2= 9

y=3

y=3/4x

For part B,I'm not sure whether it is y=-4/3x

For part C Not sure how to do it.

- Calculus -
**asia**, Friday, November 7, 2008 at 3:02amI solved the question in A but please check..

first of all you have to find y while x=4 and as you find y^2=25-16=9 and y=3

then you have to find slope. It's derivative of y function so

(slope)m=1/2(1/25-x^2)(2x).

if we write 3 instead of x we will get m(slope) as -4/3.

from

the tangent line equation

y-3=(-4/3)(x-4)

y=(-4/3)x+25/3.(result)

- Calculus -
**asia**, Friday, November 7, 2008 at 4:00amsolution for part B

for the normal line equation firstly you have to find again slope. product of tangentline's slope and normal line's slope must be -1.

there fore

line's slope.(-4/3)=-1

line's slope= 3/4

then

the line equation is

y-3= =(3/4)(x-4)

we get

y= 3x/4(result)

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