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March 29, 2015

March 29, 2015

Posted by **jeff** on Thursday, November 6, 2008 at 10:20pm.

- physics -
**drwls**, Friday, November 7, 2008 at 6:19amCan you calculate how fast an object is going after falling Y 1.3 m? Sure you can. Try using conservation of energy.

M g Y = (1/2) M V^2

For the spring constant k,

(1/2) M V^2 + M g X = (1/2) kX^2

(the energy stored in the spring when motion stips). Cancel out the M's and solve for k

Since there is no friction assumed, the ball should bounce back to its original height

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