Posted by jeff on Thursday, November 6, 2008 at 10:20pm.
Can you calculate how fast an object is going after falling Y 1.3 m? Sure you can. Try using conservation of energy.
M g Y = (1/2) M V^2
For the spring constant k,
(1/2) M V^2 + M g X = (1/2) kX^2
(the energy stored in the spring when motion stips). Cancel out the M's and solve for k
Since there is no friction assumed, the ball should bounce back to its original height
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