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March 26, 2017

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We need assistance solving

3 + 2(k+1) = 6 + 3k

I know the 2(k+1) has to become 2k + 2

then we have 3 + 2k + 2 = 6 + 3k
then we can subtract 3k from both sides to get
3 +2k + 2 - 3K = 6
But can I combine the 3+2 on the left
and the 2k - 3k to get -1k?

leaving us with 5 -1k = 6
-1k = 6-5
-1k = 1
k = -1

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