sorry for asking for help agen.

a baseball catcher puts on an exhibition by catching a .150kg ball dropped from a helicopter at a height of 100m above the catcher. if the catcher "gives with the ball for a distance of .75m while catching it, what average force is exerted on the mitt by the ball (g=9.8m/s2)?

force(distancestopped)=mgh

force(.75)=massball*g*heighthelo

thank you tahnk you. it makes sense now

No problem at all! I'm here to help.

To find the average force exerted on the mitt by the ball, we need to consider a few concepts of physics.

First, let's calculate the potential energy of the ball at the height from which it was dropped. The potential energy (PE) is given by the formula:

PE = m * g * h

Where:
m = mass of the ball = 0.150 kg
g = acceleration due to gravity = 9.8 m/s^2
h = height from which the ball was dropped = 100 m

So, substituting the given values:

PE = 0.150 kg * 9.8 m/s^2 * 100 m
PE = 147 J (joules)

Now, let's calculate the work done by the gravitational force as the ball falls. The work done (W) is given by the formula:

W = PE

Since no other non-conservative forces are acting on the ball, the work done by gravity is equal to the change in kinetic energy of the ball.

Next, we'll calculate the final velocity (v) of the ball just before it reaches the catcher's mitt using the following kinematic equation for downward freefall motion:

v^2 = u^2 + 2 * a * d

Where:
u = initial velocity of the ball (which is zero since it was dropped)
a = acceleration due to gravity = 9.8 m/s^2
d = height from which the ball was dropped = 100 m

Rearranging the equation:

v^2 = 0 + 2 * 9.8 m/s^2 * 100 m
v^2 = 1960 m^2/s^2

Taking the square root of both sides:

v = 44.3 m/s

Now, let's calculate the average force (F) exerted on the mitt by the ball. The average force is given by the formula:

F = W / s

Where:
W = work done by the gravitational force = 147 J
s = distance over which the mitt gives with the ball = 0.75 m

Substituting the given values:

F = 147 J / 0.75 m
F = 196 N (newtons)

Therefore, the average force exerted on the mitt by the ball is 196 N.