Posted by **Bryan** on Thursday, November 6, 2008 at 11:16am.

A midwestern music competition awarded 38 ribbons. The number of blue ribbons awarded was 3 less than the number of white ribbons. The number of red ribbons was 2 more than the number of white ribbons. How many of each kind of ribbon was awarded?

- math -
**gondy**, Thursday, November 6, 2008 at 11:39am
w+(w-3)+(w+2)= 38

Solve this equation to get the number of white ribbons then plug in that number to solve for the rest of the ribbons

- math -
**lulu**, Tuesday, December 2, 2008 at 6:57pm
first you add one to both sides

3w-1=38

+1 +1

then you divide both sides by 3

3w=39

/3 /3

then when you get your answer...

w=13

go back and plug in 13 in every w.Remember to follow the order of operations

13+(13-3)+(13+2)=38

13+(10)+(15)=38

38+38

:D

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