Posted by **Samantha** on Wednesday, November 5, 2008 at 12:29pm.

4) The graph of y = (x)/(1+25x^2) for x is greater than or equal to 0 has a horizontal tangent at x = what.

So what I did was find the first derivative. I did the quotient rule and ended up with

x50x - 1+25x^2

---------------

(1+25x^2)^2

I equated that with 0 but I don't know how to solve for x without using a calculator. Someone please help.

## Answer This Question

## Related Questions

- Calculus - Let f be a twice-differentiable function defined on the interval -1.2...
- Calculus c - Let f be a twice-differentiable function defined on the interval -1...
- Calculus (derivatives) - Find the points on the graph of f where the tangent ...
- Calculus - Functions? - #1. A cubic polynomial function f is defined by f(x) = ...
- cal - Determine all values of x, (if any), at which the graph of the function ...
- Calc - 1. Find values of a,b,c, and d such that g(x) = a(x^3)+b(x^2)+cx+d has a ...
- pre calc - Use the derivative of f(x) = 6x7 + 7x6 to determine any points on the...
- calculus - 1. Which of the following expressions is the definition of the ...
- calc - The function f is defined by f(x) = x^3 - x^2 - 4x + 4 The point (a,b) is...
- calc - Find an equation of the tangent line to the curve at the given point. y...

More Related Questions