Posted by **Samantha** on Wednesday, November 5, 2008 at 12:29pm.

4) The graph of y = (x)/(1+25x^2) for x is greater than or equal to 0 has a horizontal tangent at x = what.

So what I did was find the first derivative. I did the quotient rule and ended up with

x50x - 1+25x^2

---------------

(1+25x^2)^2

I equated that with 0 but I don't know how to solve for x without using a calculator. Someone please help.

## Answer This Question

## Related Questions

- Calculus - Let f be a twice-differentiable function defined on the interval -1.2...
- Calculus - Functions? - #1. A cubic polynomial function f is defined by f(x) = ...
- math - The graph of a reciprocal function of the form f(x)=1/ax+b where a is not...
- Calculus c - Let f be a twice-differentiable function defined on the interval -1...
- Math- Calc 1 - 1. At what point does the normal line to the curve x^2 - XY + Y^2...
- Math- Calc 1 - 1. At what point does the normal line to the curve x^2 - XY + Y^2...
- Calc - 1. At what point does the normal line to the curve x^2 - XY + Y^2 = 3 at ...
- ap calc - the graph of y= (ax+b)/(x-1)(x-4) has a horizontal tangent at the ...
- Calculus - The function g is defined for x>0 with g(1)=2, g'(x)=sin(x+1/x), ...
- calc - Consider the following function. f(x) = 4x3 + x2 - 0.05x + 10 Find the ...

More Related Questions