calculus
posted by kat on .
find the limit for the given function
lim (sin)^2(3 t))/t^2
t>0

Remember and apply L'Hopital's rule. (Take the ratio of the derivatives of numerator and denominator). You may have to use it twice.
OR use the fact that sin x approaches x as x> 0.
(sin)^2(3 t))/t^2 therefore approaches
(3t)^2/t^2 = 9