Posted by kat on Wednesday, November 5, 2008 at 1:44am.
find the limit for the given function
lim (sin)^2(3 t))/t^2
t>0

calculus  drwls, Wednesday, November 5, 2008 at 7:26am
Remember and apply L'Hopital's rule. (Take the ratio of the derivatives of numerator and denominator). You may have to use it twice.
OR use the fact that sin x approaches x as x> 0.
(sin)^2(3 t))/t^2 therefore approaches
(3t)^2/t^2 = 9