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December 18, 2014

December 18, 2014

Posted by **kat** on Wednesday, November 5, 2008 at 1:44am.

lim (sin)^2(3 t))/t^2

t->0

- calculus -
**drwls**, Wednesday, November 5, 2008 at 7:26amRemember and apply L'Hopital's rule. (Take the ratio of the derivatives of numerator and denominator). You may have to use it twice.

OR use the fact that sin x approaches x as x-> 0.

(sin)^2(3 t))/t^2 therefore approaches

(3t)^2/t^2 = 9

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