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calculus

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find the limit for the given function

lim (sin)^2(3 t))/t^2
t->0

  • calculus - ,

    Remember and apply L'Hopital's rule. (Take the ratio of the derivatives of numerator and denominator). You may have to use it twice.

    OR use the fact that sin x approaches x as x-> 0.
    (sin)^2(3 t))/t^2 therefore approaches
    (3t)^2/t^2 = 9

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