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Posted by on Wednesday, November 5, 2008 at 1:44am.

find the limit for the given function

lim (sin)^2(3 t))/t^2
t->0

  • calculus - , Wednesday, November 5, 2008 at 7:26am

    Remember and apply L'Hopital's rule. (Take the ratio of the derivatives of numerator and denominator). You may have to use it twice.

    OR use the fact that sin x approaches x as x-> 0.
    (sin)^2(3 t))/t^2 therefore approaches
    (3t)^2/t^2 = 9

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