Posted by i love polka on .
the sensor in the torso of a crashtest dummy records the magnitude and direction of the net force acting on the dummy. if the dummy is thrown forward with a force of 130.0 N while simultaneously being hit from side with a force of 4500.0 N, what force will the sensor report?
what force will the seat belt have to exert on the dummy to hold the dummy in the seat?

physics 
Damon,
sqrt (130^2 + 4500^2)
tan angle from straight ahead = 4500/130
seat belt equal and opposite 
physics 
Emanuela,
4500/130= 34.6N

physics 
Krys,
sqrt (130^2 + 4500^2) = 4501.8 N
tan(angle) (4500.0/130.0) 
physics 
Kay Crum,
you subtract 130 from 4500, and you get 4470 :)

Physics 
Kyser,
sqrt (130^2 + 4500^2) = 4501.9N
tan(angle) = (opp/adj)
Angle = (tan^1)(4500/130)
Angle = 88.3 degrees to the side of forward
Answer: 4501.9N @88.3 degrees to the side of forward
(answer due to opposite of what sensor reads) 
physics 
Anonymous,
5. The sensor in the torso of a crashtest dummy records the magnitude and direction of the net force acting on the dummy. If the dummy is thrown forward with a force of 130.0 N while simultaneously being hit from the side with a force of 4500.0 N, what force will the sensor report?