# physics

posted by on .

the sensor in the torso of a crash-test dummy records the magnitude and direction of the net force acting on the dummy. if the dummy is thrown forward with a force of 130.0 N while simultaneously being hit from side with a force of 4500.0 N, what force will the sensor report?

what force will the seat belt have to exert on the dummy to hold the dummy in the seat?

• physics - ,

sqrt (130^2 + 4500^2)

tan angle from straight ahead = 4500/130

seat belt equal and opposite

• physics - ,

4500/130= 34.6N

• physics - ,

sqrt (130^2 + 4500^2) = 4501.8 N

tan(angle) (4500.0/130.0)

• physics - ,

you subtract 130 from 4500, and you get 4470 :)

• Physics - ,

sqrt (130^2 + 4500^2) = 4501.9N
Angle = (tan^-1)(4500/130)
Angle = 88.3 degrees to the side of forward

Answer: -4501.9N @-88.3 degrees to the side of forward

• physics - ,

5. The sensor in the torso of a crash-test dummy records the magnitude and direction of the net force acting on the dummy. If the dummy is thrown forward with a force of 130.0 N while simultaneously being hit from the side with a force of 4500.0 N, what force will the sensor report?​