Post a New Question

physics

posted by on .

the sensor in the torso of a crash-test dummy records the magnitude and direction of the net force acting on the dummy. if the dummy is thrown forward with a force of 130.0 N while simultaneously being hit from side with a force of 4500.0 N, what force will the sensor report?

what force will the seat belt have to exert on the dummy to hold the dummy in the seat?

  • physics - ,

    sqrt (130^2 + 4500^2)

    tan angle from straight ahead = 4500/130

    seat belt equal and opposite

  • physics - ,

    4500/130= 34.6N

  • physics - ,

    sqrt (130^2 + 4500^2) = 4501.8 N

    tan(angle) (4500.0/130.0)

  • physics - ,

    you subtract 130 from 4500, and you get 4470 :)

  • Physics - ,

    sqrt (130^2 + 4500^2) = 4501.9N
    tan(angle) = (opp/adj)
    Angle = (tan^-1)(4500/130)
    Angle = 88.3 degrees to the side of forward

    Answer: -4501.9N @-88.3 degrees to the side of forward

    (answer due to opposite of what sensor reads)

  • physics - ,

    5. The sensor in the torso of a crash-test dummy records the magnitude and direction of the net force acting on the dummy. If the dummy is thrown forward with a force of 130.0 N while simultaneously being hit from the side with a force of 4500.0 N, what force will the sensor report?‚Äč

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question