Posted by **Samantha** on Tuesday, November 4, 2008 at 8:05pm.

y = e^2xsin3x Find the derivative.

So I used the product rule and I got sin3x(e^2x)+cos^3x(e^2x). But the actual answer is sin3x(2e^2x)+cos^3x(3e^2x) Where the the 2 and 3 before the e come from?

- Calculus part 3 so sorry -
**Damon**, Tuesday, November 4, 2008 at 8:55pm
I guess you mean

[e^(2x)]sin 3x

sin 3x [2 e^(2x)] + 3 cos (3x) e^(2x)

hey same mistake as earlier

d/dx (e^u) = du/dx * e^u

and

d/dx (sin u) = du/dx cos u

if u = 2x, then du/dx = 2

if u = 3x, then du/dx = 3

## Answer this Question

## Related Questions

- Calculus - In the interval (0 is less than or equal to x which is less than or ...
- Maths - given (e^x)sin3x = Im((e^x)(e^i3x)) Integrate (e^x)sin3x.dx You can just...
- Trig - I have these sum and product property problems and I just want to make ...
- trig - I have these sum and product property problems and I just want to make ...
- Calculus 12th grade (double check my work please) - 1.)Find dy/dx when y= Ln (...
- maths - If (e^x)(sin3x)=Im ((e^x)(e^i3x)) integrate (e^x)(sin3x) I get the ...
- Cos-Derivative - y= (cos^3 x) (cos 3x) I got -3 sin(3x) cos^3x - 3 sin(x) cos (...
- Alegbra 2 - how do i find out what the amplitude, period, h, k and midline of ...
- Calculus - Find the derivative of cos(sqrt(e^(x^3)cos(x)) I got -sin(sqrt(e^(x^3...
- Calculus - please check my work - differentiate each function a) y = cos^3x b) y...

More Related Questions