Saturday
April 19, 2014

Homework Help: Calculus Part 2

Posted by Samantha on Tuesday, November 4, 2008 at 8:01pm.

y = tan(sqrtx)
Find dy/dx.
So I found it and I got the answer as sec^2(sqrtx) but the answer is (sec^2(sqrtx))/2(sqrtx)...why?
----------------------------------

2) Find the line which passes through the point (0, 1/4) and is tangent to the curve y=x^3 at some point.
So I found the derivative which is 3x^2.
Let (a, a3) be the point of tangency.

3x^2 = (a3 - 1/4)/(a-0)
I'm not sure how to solve for a.

Can someone please help me out with these? I have an exam tomorrow evening and these questions are a lost cause.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Calculus - lim(x->infinity) sqrtx sin(1/sqrtx) Someone please start me off. I...
Calculus - I don't know how to do the integral of e^(lnx^2)dx and the integral ...
math - Please help me simplify: 4sqrtx^12/24sqrtx^2 *Is this correct: 2sqrt4/12x...
Integration - Intergrate sec^3(x) dx could anybody please check this answer. ...
Business Cal - Suppose a publishing company has found that the marginal cost at ...
calculus - find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx ...
calculus (check my work please) - Not sure if it is right, I have check with the...
Calc - Find the equation of the tangent line to f(x)=sqrtx^2+6x at x=2, give ...
finding c: calc - let f(x)=square root x. if the rate of change of at x=c is ...
Calculus - Find the partial derivative for x. f(x,y)=1/SQRTx^2+y^2

Search
Members