What is the geometry of S2O82-
its basically two SO4 molecules connected by the O-O bond
how do u draw the lewis structure of F3S-SF
Write "F-S-S-F".
Above and below the first "S", write "F".
The geometry of the S2O8 2- ion can be described as disordered or distorted octahedral.
In a simplified representation, the two SO4 (sulfate) molecules are connected by an O-O bond. Each sulfate molecule has a tetrahedral geometry, with four oxygen atoms surrounding a central sulfur atom.
The O-O bond that connects the two sulfate molecules introduces an additional atom and distorts the symmetrical octahedral geometry. The central O-O bond causes a bending or distortion in the structure, resulting in a disordered geometry.
Overall, the S2O8 2- ion can be thought of as having a combination of tetrahedral and octahedral geometry.
To determine the geometry of the S2O8^2- ion, you can start by looking at the Lewis structure of the molecule. The Lewis structure helps determine the arrangement of atoms and lone pairs around the central atom.
In this case, the central atom is sulfur (S). S2O8^2- contains two sulfate (SO4) groups bonded together by an oxygen-oxygen (O-O) bond. Each sulfate group has a tetrahedral geometry, with the sulfur atom at the center surrounded by four oxygen atoms.
When the two sulfate groups are connected by the O-O bond, the resulting geometry is called a dimer. The dimer is often described as having a "butterfly" shape, with the two sulfur atoms forming the wings and the O-O bond representing the body.
Therefore, the S2O8^2- ion has a dimeric geometry, resembling a butterfly shape.