2. Why doesn’t the neutral organic compound (Flourene) dissolve in 1.5 M sodium hydroxide solution?
Did you mean fluorene? Fluorene is a hydrocarbon, much like naphthalene or anthracene. Materials that are soluble in NaOH solution usually are soluble in water alone or they are acidic in nature. I'm not an organic chemist but I wouldn't expect fluorene to be soluble in NaOH.
http://en.wikipedia.org/wiki/Fluorene
Well, Flourene must be like that quirky friend who just doesn't like to socialize with everyone. Sodium hydroxide solution can be a bit too strong and basic for Flourene's taste. It probably prefers to hang out in neutral environments, where it can really shine. So, you can think of it as Flourene being a bit of a picky partygoer that chooses not to dissolve in the sodium hydroxide solution.
The reason flourene does not dissolve in a 1.5 M sodium hydroxide solution can be attributed to the difference in solubility and chemical properties.
1. Solubility: Flourene is a hydrophobic (water-insoluble) organic compound, meaning it does not readily dissolve in water or aqueous solutions. Sodium hydroxide (NaOH), on the other hand, is highly soluble in water and dissociates into its constituent ions, Na+ and OH-. Since flourene is not soluble in water, it is unlikely to dissolve in a sodium hydroxide solution.
2. Chemical properties: Sodium hydroxide is a strong base and has a high pH. Flourene, being a neutral compound, does not have acidic or basic properties. Therefore, there is no specific chemical interaction or affinity between flourene and sodium hydroxide that would promote dissolution.
In summary, the inability of flourene to dissolve in a 1.5 M sodium hydroxide solution is primarily due to its low solubility in water and the absence of chemical interactions with sodium hydroxide.
To understand why the neutral organic compound fluorene does not dissolve in a 1.5 M sodium hydroxide (NaOH) solution, we need to consider the chemical properties of fluorene and the nature of the solution.
The solubility of a substance in a given solvent depends on several factors, including the polarity and intermolecular forces involved. In this case, fluorene is a nonpolar organic compound, while sodium hydroxide is a highly polar ionic compound.
Fluorene is made up of carbon and hydrogen atoms, which are connected by covalent bonds. It is nonpolar because the electronegativity values of carbon and hydrogen are similar, resulting in an equal sharing of electrons within the molecule. Nonpolar compounds are generally insoluble in polar solvents like water or ionic solutions like sodium hydroxide.
Sodium hydroxide, on the other hand, is an ionic compound formed from the combination of sodium ions (Na+) and hydroxide ions (OH-). In water, sodium hydroxide dissociates into its constituent ions, creating a solution of sodium ions and hydroxide ions. These ions are highly polar due to the difference in electronegativity between sodium and oxygen. The polar nature of sodium hydroxide creates strong attractions with other polar or charged molecules.
Since fluorene is a nonpolar compound, it lacks the charge or polarity that would allow it to interact strongly with the polar hydroxide ions in the sodium hydroxide solution. As a result, the intermolecular forces between fluorene molecules are stronger than the forces between fluorene and the hydroxide ions. This makes it difficult for fluorene to dissolve in the sodium hydroxide solution.
In summary, fluorene does not dissolve in a 1.5 M sodium hydroxide solution because it is a nonpolar compound that is unable to form strong interactions with the polar hydroxide ions in the solution.