Homework Help: PHYSICSS!!!!!

Posted by jacky on Tuesday, November 4, 2008 at 1:10am.

At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of vi = (3.00 i - 2.00 j) m/s and is at the origin. At t = 2.00 s, the particle's velocity is v = (6.60 i + 4.00 j) m/s.

Find the acceleration of the particle at any time t. (Use t, i, and j as necessary.)

PHYSICSS!!!!! - drwls, Tuesday, November 4, 2008 at 3:09am
Subtract the two vector velocities from one another and divide the difference by 2.00 s to get the vector acceleration.

Since acceleration is said to be constant, it will be valid at all t.

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