Post a New Question

AP Chem

posted by on .

A solution of hydrogen peroxide, H2O2, is titrated with a solution of potassium permanganate, KMnO4.

It requires 51.7 mL of 0.145 M KMnO4 to titrate 20.0 g of the solution of hydrogen peroxide. What is the mass percentage of H2O2 in the solution?

If you want the whole equation I'll type it but it's long. I think all you need is the mole ratio which is 5 mol H202 : 2 mol KMnO4.

so far I changed 51.7 mL to L. Got .00750 mol KMnO4 using molarity and volume. converted that to .0188 mol H2O2.

  • AP Chem - ,

    You may have almost finished it then but I'll start from the beginning.
    Convert M x L KMnO4 to mols.
    Convert mols KMnO4 to mols H2O2 using the coefficients in the balanced equation.
    Convert mols H2O2 to grams H2O2.
    Then %H2O2 = [grams H2O2/mass of sample]*100.
    Mass of the sample is 20.0 g in the problem.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question