Posted by jane on Monday, November 3, 2008 at 10:10pm.
Rewrite as [sin x(1 - 1/cosx)]/sin^3x
= [1 - (1/cosx)]/[1 - cos^2x]
Now use L'Hopital's rule and take the ratio of the derivatives of numerator and denominator. That lets you get rid of the 1's.
You are left with
Lim [-tanx secx/(2cosx sinx)]
= Lim -1/(2 cos^3x)
Which is -1/2
It took me a while to get that one. I cheated and used a hand calculator first, and it agrees.
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