Complete and balance each of the following molecular equations, including phase labels, if a reaction occurs. Then write the net ionic equation. If no reaction occurs, write NR after the arrow.
H2CO3(aq)+Sr(OH)2(aq) ->
this is what I put but I think its wrong
H2CO3(aq)+Sr(OH)2(aq) -> SrO(aq)+CO2(g)+H2O(l)
H2CO3(aq)+2OH^-(aq) -> O^-2(aq)+CO2(g)+H20(l)
Yes, thank you. I was trying to do the equation like it was a carbonate that produced carbon dioxide, not as an acid.
To complete and balance the given molecular equation, first write the chemical formula for each compound:
H2CO3(aq) + Sr(OH)2(aq) ->
The next step is to identify the products of the reaction. In this case, H2CO3 is a weak acid and Sr(OH)2 is a strong base.
H2CO3(aq) + Sr(OH)2(aq) -> SrCO3(aq) + H2O(l)
Next, balance the equation by ensuring the same number of atoms on each side:
H2CO3(aq) + Sr(OH)2(aq) -> SrCO3(aq) + 2H2O(l)
Now, write the net ionic equation by canceling out any spectator ions. Spectator ions are the ions that appear on both sides of the equation and do not participate in the actual reaction. In this case, the only spectator ion is Sr^2+, while CO3^2- is the only ion involved in a chemical change:
2H^+(aq) + CO3^2-(aq) -> H2O(l)
Therefore, the net ionic equation is:
2H^+(aq) + CO3^2-(aq) -> H2O(l)
There is no need to mention the solid state of SrCO3, as it is assumed to be present as ions in aqueous solution.
To complete and balance the molecular equation for the reaction between H2CO3 (carbonic acid) and Sr(OH)2 (strontium hydroxide), let's look at the combination of ions to form the products:
H2CO3(aq) + Sr(OH)2(aq) ->
First, let's identify the ions involved. H2CO3(aq) dissociates into H+ and HCO3- ions, while Sr(OH)2(aq) dissociates into Sr2+ and 2OH- ions.
H2CO3(aq) + Sr(OH)2(aq) -> 2H+(aq) + HCO3-(aq) + Sr2+(aq) + 2OH-(aq)
Now, let's check if the ions can combine to form any insoluble compounds or a gas. If so, a reaction occurs. In this case, HCO3- and Sr2+ do not form any insoluble compounds, but they can combine to produce water and carbon dioxide gas.
2H+(aq) + HCO3-(aq) + Sr2+(aq) + 2OH-(aq) -> H2O(l) + CO2(g) + Sr2+(aq) + 2OH-(aq)
Next, we can cancel out the spectator ions, which are the Sr2+ and OH- ions present on both sides of the equation:
2H+(aq) + HCO3-(aq) + 2OH-(aq) -> H2O(l) + CO2(g)
This is the complete and balanced molecular equation.
To obtain the net ionic equation, we remove the spectator ions from the equation:
H+(aq) + HCO3-(aq) + OH-(aq) -> H2O(l) + CO2(g)
The net ionic equation represents the actual chemical changes in the reaction.
You're right. It isn't correct.
Look at the reactants. H2CO3 is an acid. Sr(OH)2 is a base. The general reaction for an acid and a base produces a salt plus water.
H2CO3 + Sr(OH)2 ==> H2O + SrCO3
Can you add the (aq), (l), (s) to the materials? It isn't balanced. Can you balance it and can you write the net ionic equation now that I've written the molecular equation.