Posted by Kiley on Monday, November 3, 2008 at 5:52pm.
Find the vertex and axis of symmetry of the parabola when y=3x^2+128

Algebra 2  drwls, Monday, November 3, 2008 at 7:35pm
Don't you mean
y = 3x^2 +12x 8 ?
If so, "complete the square" and rewrite it as
y = 3(x^2 + 4x + 4) 20
= 3(x+2)^2 20
That is symmetric about x = 2, and has a vertex at
x = 2, y = 20

Algebra 1  michael, Thursday, April 12, 2012 at 4:34pm
how to graph
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