Posted by **Kiley** on Monday, November 3, 2008 at 5:52pm.

Find the vertex and axis of symmetry of the parabola when y=-3x^2+12-8

- Algebra 2 -
**drwls**, Monday, November 3, 2008 at 7:35pm
Don't you mean

y = 3x^2 +12x -8 ?

If so, "complete the square" and rewrite it as

y = 3(x^2 + 4x + 4)- 20

= 3(x+2)^2 -20

That is symmetric about x = -2, and has a vertex at

x = -2, y = -20

- Algebra 1 -
**michael**, Thursday, April 12, 2012 at 4:34pm
how to graph

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