Posted by
Kiley on
.
Find the vertex and axis of symmetry of the parabola when y=3x^2+128

Algebra 2 
drwls,
Don't you mean
y = 3x^2 +12x 8 ?
If so, "complete the square" and rewrite it as
y = 3(x^2 + 4x + 4) 20
= 3(x+2)^2 20
That is symmetric about x = 2, and has a vertex at
x = 2, y = 20

Algebra 1 
michael,
how to graph