Posted by Kyle on Monday, November 3, 2008 at 9:32am.
A bowling ball encounters a 0.76 m vertical rise on the way back to the ball rack, as the drawing illustrates. Ignore frictional losses and assume that the mass of the ball is distributed uniformly. If the translational speed of the ball is 5.40 m/s at the bottom of the rise, find the translational speed at the top.
Do you use the equation for total mechanical energy and if so how do you get the mass and radius?

Physics  Count Iblis, Monday, November 3, 2008 at 10:20am
What happens is that in the answer the mass and the radius drops out.
The total kinetic energy is:
Ekin = 1/2 m v^2 + 1/2 I omega^2
If the ball rolls without slipping, then:
omega = v/R
The moment of intertial of the ball is:
I = 2/5 m R^2
So, the kinetic energy is:
Ekin = 1/2 m v^2 + 1/5 m v^2 =
7/10 m v^2
The potential energy is mgh, so the total energy of the ball is at height h and velocity v is
E(h,v) = m g h + 7/10 m v^2 =
m [g h + 7/10 v^2]
The total energy is conserved, so you can find the velocity at the top by solving:
E(h=0.76 meter, v ) = E(0, v = 5.40 m/)
The unknown mass m drops out.
Answer This Question
Related Questions
 Physics  A bowling ball encounters a 0.760m vertical rise on the way back to ...
 Physics  A bowling ball encounters a 0.760 m vertical rise on the way back to ...
 physics  A bowling ball encounters a 0.760m vertical rise on the way back to ...
 Physics  A bowling ball encounters a 0.76m vertical rise on the way back to ...
 Physics  Equate the increase in potential energy at the higher elevation, M g H...
 physics  A bowling ball encounters a 0.76m vertical rise on the way back to ...
 Physics please check  A bowling ball encounters a 0.76 m vertical rise on the ...
 Physics  After you pick up a spare, your bowling ball rolls without slipping ...
 physics  After you pick up a spare, your bowling ball rolls without slipping ...
 Physics  After you pick up a spare, your bowling ball rolls without slipping ...
More Related Questions