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April 1, 2015

April 1, 2015

Posted by **Bertrand** on Monday, November 3, 2008 at 8:25am.

I'm still confused about how you got the (1/8)kx^2 and how to find the weight's maximum height at the top of its path through the air.

- Physics -
**bobpursley**, Monday, November 3, 2008 at 10:29amI dont know about your 1/8kx^2 you posted above, I didn't see it in the post.

If you know the initial potential energy, 1/2 kx^2, that has to turn to gravitational PE mgh at the max height.

set them equal, and solve for h.

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