Posted by Bertrand on Monday, November 3, 2008 at 8:25am.
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I'm still confused about how you got the (1/8)kx^2 and how to find the weight's maximum height at the top of its path through the air.

Physics  bobpursley, Monday, November 3, 2008 at 10:29am
I don't know about your 1/8kx^2 you posted above, I didn't see it in the post.
If you know the initial potential energy, 1/2 kx^2, that has to turn to gravitational PE mgh at the max height.
set them equal, and solve for h.
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