Posted by **Mary** on Monday, November 3, 2008 at 1:03am.

A thin, uniform rod is bent into a square of side length a.

If the total mass is M , find the moment of inertia about an axis through the center and perpendicular to the plane of the square. Use the parallel-axis theorem.

Express your answer in terms of the variables M and a.

PLEASE HELP WITH A THOROUGH EXPLANATION PLEASE!!!

- Inertia -
**bobpursley**, Monday, November 3, 2008 at 5:04am
We may disagree on thorough explaination. I am not doing students work for them.

Look at the square. It has sides a/4, and M/4. Now if you look at it from the center, the moment of inertia could be calculated from the I of any of those rods, moved with the parallel axis theorm to the center (a distance of a/8), then multiplyied by 4 due to all the rods contribution.

I will be happy to critique your thinking or work. Repost if if you need help.

- Inertia -
**Mary**, Monday, November 3, 2008 at 1:21pm
so would I = ma^2? i am confused

- Inertia -
**jarded**, Tuesday, December 1, 2015 at 12:48am
billy

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