Tuesday

January 27, 2015

January 27, 2015

Posted by **sarah** on Monday, November 3, 2008 at 12:22am.

- science -
**drwls**, Monday, November 3, 2008 at 2:21amThe acceleration is

dv/dt = 32t i + 12 t^2 j + 5 k

Plug in t = 2 to get the acceleration vector at t =2.

The position vector is the integral of v(t),

r(t) = [(16/3)t^3 + a]i +

(t^4 + b)j + [(5/2)t^2 + 2t + c] k

where a, b and c are constants of integration. Use the position at t = 0 to solve for them. It appears that a=b=c=0

**Answer this Question**

**Related Questions**

Calculus - The position of a particle moving on a horizontal line is given by s(...

Physics - A particle moving initially at 4 m/s in the positive x direction is ...

Calculus-particle motion - 1. A particle is moving on the x-axis (or any number ...

calculus - 5. A particle moves along the x-axis in such a way that its position ...

physics - The position of a particle moving along an x axis is given by x = 15t2...

Physics - A particle starts from the origin with velocity 2i m/s at t = 0 and ...

univercity of baghdad - A particle travels along a straight line with a velocity...

Physics-can anyone check my work? - A particle starts from the origin with ...

physics help - The magnitude of the velocity of a particle which starts from ...

physics help - The magnitude of the velocity of a particle which starts from ...